영어로 읽는 코딩

37_[자바] 초기화 4 (정적변수의 초기화)

static data initialization

There’s only a single piece of storage for a static, regardless of how many objects are created. You can’t apply the static keyword to local variables, so it only applies to fields. If a field is a static primitive and you don’t initialize it, it gets the standard initial value for its type. If it’s a reference to an object, the default initialization value is null.

If you want to place initialization at the point of definition, it looks the same as for non-statics.

To see when the static storage gets initialized, here’s an example:

//: initialization/StaticInitialization.java
// Specifying initial values in a class definition.
import static net.mindview.util.Print.*;
class Bowl {
    Bowl(int marker) {
	print("Bowl(" + marker + ")");
	}
	void f1(int marker) {
	print("f1(" + marker + ")");
	}
}
class Table {
	static Bowl bowl1 = new Bowl(1);
	Table() {
		print("Table()");
		bowl2.f1(1);
	}
	void f2(int marker) {
		print("f2(" + marker + ")");
	}
	static Bowl bowl2 = new Bowl(2);
}
class Cupboard {
	Bowl bowl3 = new Bowl(3);
	static Bowl bowl4 = new Bowl(4);
	Cupboard() {
		print("Cupboard()");
		bowl4.f1(2);
	}
	void f3(int marker) {
	print("f3(" + marker + ")");
	}
	static Bowl bowl5 = new Bowl(5);
}
public class StaticInitialization {
	public static void main(String[] args) {
		print("Creating new Cupboard() in main");
		new Cupboard();
		print("Creating new Cupboard() in main");
		new Cupboard();
		table.f2(1);
		cupboard.f3(1);
	}
	static Table table = new Table();
	static Cupboard cupboard = new Cupboard();
} /* Output:
Bowl(1)
Bowl(2)
Table()
f1(1)
Bowl(4)
Bowl(5)
Bowl(3)
Cupboard()
f1(2)
Creating new Cupboard() in main
Bowl(3)
Cupboard()
f1(2)
Creating new Cupboard() in main
Bowl(3)
Cupboard()
f1(2)
f2(1)
f3(1)
*///:~

Bowl allows you to view the creation of a class, and Table and Cupboard have static members of Bowl scattered through their class definitions. Note that Cupboard creates a non-static Bowl bowl3 prior to the static definitions.

From the output, you can see that the static initialization occurs only if it’s necessary. If you don’t create a Table object and you never refer to Table.bowl1 or Table.bowl2, the static Bowl bowl1 and bowl2 will never be created. They are initialized only when the first Table object is created (or the first static access occurs). After that, the static objects are not reinitialized.

The order of initialization is statics first, if they haven’t already been initialized by a previous object creation, and then the non-static objects. You can see the evidence of this in the output. To execute main( ) (a static method), the StaticInitialization class must be loaded, and its static fields table and cupboard are then initialized, which causes those classes to be loaded, and since they both contain static Bowl objects, Bowl is then loaded. Thus, all the classes in this particular program get loaded before main( ) starts. This is usually not the case, because in typical programs you won’t have everything linked together by statics as you do in this example.

 

 

[Thinking in Java, 128]

댓글

댓글 본문
버전 관리
Yoo Moon Il
현재 버전
선택 버전
graphittie 자세히 보기